Plz ! will mark the !
the system mx+ny=p has the solution (1,3), where rx+sy=t
m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.

C.

Step-by-step explanation:

Given: The system has the solution (1,3), where M,N,P,R,S and T are non zero real numbers.

A.

Divide 7 on both sides on the second equation , we will get

Thus, this system has solution (1,3)

B.

Subtract equation (2) from equation (1), we get

Thus, this system has solution (1,3)

C.

We can rewrite the equation (2) as

Multiply 2 on both sides of equation (1), we get

Subtract equation (3) from (4), we get

But

Thus, this system does not have solution as (1,3).

D.

Multiply 2 on both sides on the first equation , we will get

Thus, this system has solution (1,3)

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

no

step-by-step explanation: