Ablimp is 1300 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. if those measurements are 71.9° and 27.1°, how far apart are the two stadiums to the nearest meter?

Tanα=height/distance

tanα=h/d

d=h/tanα  so

d1=h/tanα  and d2=h/tanß

Then the distance between them is:

d=h/tanß-h/tanα, we know that h=1300, α=71.9°, and ß=27.1° so

d=3100/tan27.1-3100/tan71.9 meters

d≈5045 m (to nearest meter)

300b(x) is graphed by the functio