The length of a rectangle is 7 inches more than its width. the area of the rectangle is equal to 2 inches less than 5 times the perimeter . what is the length and width

Let the width be w, then the length is w+7 units.

The area of the rectangle is .

The perimeter of the rectangle is: 

P = 2(Width + Length)=2(w+w+7)=2(2w+7)=4w+14

"The area of the rectangle is equal to 2 inches less than 5 times the perimeter." means that:

A = 5P - 2







to solve the quadratic equation, let's use the quadratic formula

let a=1, b=-13, c=-68



the root of the discriminant is 21

the roots are

w1=(13+21)/2=34/2=17
and
w2=(13-21)/2=-8/2=-4, which cannot be the width.

The width is 17 units, and the length is 17+7=24 units

w=17, l=24

For a 0.25 pfor b o.3pp (0.25+0.3)=0.28

The answer is b: step 2.