Apolynomial function has a root of –6 with multiplicity 3 and a root of 2 with multiplicity 4. if the function has a negative leading coefficient and is of odd degree, which could be the graph of the function?

step-by-step explanation:

if a polynomial function is having a root as (-6) with multiplicity of 3 and another root of 2 with multiplicity of 4 then (x + 6) and (x -2) are the two zero factors.

roots   (-6) multiplicity 3

            (2) multiplicity 4

since multiplicity of (-6) is odd then graph will cross x axis at x = -6.

now the function has a root x = 2 with multiplicity even therefore graph will touch x axis at x = 2 and further bounces up.

because they could drop even lower..

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2