The probability that a student owns a car is 0.65, and the probability that a student owns a computer is 0.82. if he probability that a student owns both is 0.55, what is the probability that a given student owns neither a car nor a computer?

If we draw a Venn diagram, we can see that the 0.55 is the intersection of probability owning a car and probability owning a computer. To solve for the probability that the student owns neither, we need to solve first for other variables.

The probability that a student owns a car but not a computer is:

P (owns a car but not computer) = 0.65 – 0.55 = 0.10

The probability that a student owns a computer but not a car is:

P (owns a car but not computer) = 0.82 – 0.55 = 0.27

Therefore the probability of owning neither is:

P (own neither) = 1 – 0.10 – 0.27 – 0.55

P (own neither) = 0.08

Therefore there is a 8% probability that the student owns neither a car or a computer.

step-by-step explanation:

just plug in each number for x and see which ones work and don't

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*