If the mcd of two numbers is 18 and the mcm is 27, calculate the product of those numbers

Product=MCM×MCD
=27× 18=486 ANS!!
And if it was to find two no. then suppose 'x' and 'y' whose MCD is. 18 and MCM is 27
Then MCD=18A AND MCM=18B where, A and B are relative prime numbers.
SO, 18AB=LCM (or MCM) of x and y
{ why b'coz MCM of any 2 numbers is multiple
of common factors and remaining factor}
or,18AB=27
or, AB=27/18=1.5
SINCE , products of two integers can't be non-integer..these two no doesn't exist. But yeah, if their MCD was 9 and MCM was 27 then we could have found the two required numbers.

The answer would be 5< 6n