What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

x2 + y2 − 4x + 2y + 1 = 0

x2 + y2 + 4x − 2y + 1 = 0

x2 + y2 + 4x − 2y + 9 = 0

x2 − y2 + 2x + y + 1 = 0

Hello : 
the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)is :
 x² + y² + 4x − 2y + 1 = 0
because :
(x²+4x)+(y²-2y+1)=0
(x²+4x+4) -4 +(y²-2y+1) =0
(x+2)² + (y-1)² = 2²(the general form )
the center is : (-2 ,1)
passing through (-4, 1) because : x=- 4 and y =1
(-4+2)² + (1-1)² =2²=4... (right)

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