Agumball machine contains red, orange, yellow, green, and blue gumballs. twenty percent of the gum balls are red, 30% are orange, 5% are yellow, 10% are green, and the rest are blue. if there are a total of 120 gumballs, how many more blue gumballs are there than yellow gumballs?

In this case, we are only interested with the number of blue gumballs and yellow gumballs. In the given, it is stated that there are 5% yellow gumballs while the percentage of the blue gumball is yet to be calculated.

The total percent should be 100%, therefore the % blue gumballs is:

% blue gumballs = 100% - 20% - 30% - 5% - 10%

% blue gumballs = 35%

Therefore the total number of each gumballs for each color is:

yellow gumballs = 120 * 0.05 = 6

blue gumballs = 120 * 0.35 = 42

Hence, 42 – 6 = 36

Therefore there are 36 more blue gumballs than there are yellow gumballs.

my answer is$ 12

step-by-step explanation:

because 15 -2=12

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral