Acar traveled for 6 hours on one highway and for 2 hours on a second highway. if the total distance traveled was 488 miles, and the car traveled 12 miles per hour faster on the second highway, at what average speed was the car traveling on the second highway?

6V + 2(V+12) = 488
8V = 464
V = 58 mph for 6 hours

V+12=70 mph for 2 hours.

 check: 58*6 = 348

             70*2 = 140

348 +140 =488

 the car was traveling at 70 mph on the 2nd highway

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

step-by-step explanation:

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