Ajar contains a combination of 60 nickels and dimes worth a total of $4.30. suppose that is deemed desirable to determine how many of each kind of coin are in the jar.

We will represent everything in cents
nickles are worth 5 cents and dimes are 10 cents
n=number of nickles
d=number of dimes

60 total coins
n+d=60

total is 430 cents

5n+10d=430
divide both sides by 5
n+2d=86

we gots

n+d=60 and
n+2d=86
eliminate

multiply first equation by -1 and add to 2nd equation

-n-d=-60
n+2d=86 +
0n+1d=26

d=26

so

n+d=60
n+26=60
n=34

34 nickles and 26 dimes

Lol idk ask google. ejie