What is the focus of the parabola given by -1/4(y+2)^2=(x-1)

so, is a horizontal parabola, the "p" distance is 1, however, we ended up with a negative value, that means, the parabola is opening to the left-hand-side, with a vertex at (1, -2), and its focus at 0, -2, like you see in the picture below, one unit to the left of the vertex.

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