Which equation is in point-slope form and is depicted by the line in this graph?

a) (y-3) = 3/5 (x-2)
b) (y-3) = -3/5 (x+2)
c) (y-3) = 5/3 (x-2)
d) (y-3) = 5/3 (x+2)

Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m

so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so

points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)

so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer