The standard for of the equation of a parabola is y=x^2+4x+11. what is the vertex for of the equation?

Convert to vertex form

or easier
for y=ax²+bx+c
the x value of the vertex is
and the y value is found by subsituting the x value in for x

so
y=1x²+4x+11
a=1
b=4

the x value of the vertex is

the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7

the vertex is (-2,7)

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