Aball is thrown in the air and it's height in feet, at any time, in seconds, is represented by the equation (h (t)=-4^2+16)when is the ball higher than 12 feet of the ground

To determine the time when the ball would be higher than 12 feet off the ground, we use the equation given which relates time and the height. It is given as:

h(t)=-4t^2 + 16

By substituting 12 to the height, we solve for the value of t.

h(t)=-4t^2 + 16
12 =-4t^2 + 16
-4 = -4t^2
t = 0 s
Therefore, the ball would never reach a height of 12 feet or higher than that or it can represent that the ball is thrown at a height of 12 feet so any time greater than 0 the ball is higher than 12 feet.

Ithink it's the first one ( let me know if it right)