The length of a rectangle is twice the width. find the width if the perimeter is 60 centimeters. define a variable, write an equation, and solve the problem.

The dimensions (length and width) of the rectangle are 20 and 10 centimeters respectively.

Given the following data:

Translating the word problem into an algebraic equation, we have;

To find the dimensions (length and width) of the rectangle;

Mathematically, the perimeter of a rectangle is given by the formula;

Substituting the values into the formula, we have;

Width, W = 10 centimeters

Next, we would find the value of L;

Substituting the value of W, we have;

Length = 20 centimeters

Therefore, dimensions (length and width) of the rectangle are 20 and 10 centimeters respectively.

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width = w

length = 2w

perimeter = 2w + 2 l

perimeter = 2w +2(2w)

60 = 2w + 4w

60= 6w

60=6w

w = 60/6 = 10

length = 10x2 = 20

10+10+20+20 = 60

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step-by-step explanation:

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents