Suppose 6 quarts of a solution that is 52% antifreeze is mixed with 10 quarts of a solution that is 32% antifreeze. (a) how many quarts of antifreeze are in the resulting mixture?

The total amount of the resulting mixture can be calculated by adding up the volume of the given substances assuming that volume addition is applicable given the properties of the fluids used. 

That is,
   T = 6 quarts + 10 quarts = 16 quarts

The total volume of the resulting mixture is 16.

Then, we do the component (antifreeze) balance by adding up the resulting antifreeze from the substances to the total. We let x be the percentage of antifreeze in the final mixture.

    6(0.52) + 10(0.32) = 16(x)

The value of x from the equation is 0.395.

Therefore, the answer to this item is 39.5%. 

The answer would be 10.