Alinear relation passes through the points (-40,19) and (24,91). determine equations for the relation in slope intercept form, general form, and slope point form

(-40,19)(24,91)
slope = (91 - 19) / (24 - (-40) = 72/64 = 9/8

y = mx + b
slope(m) = 9/8
use either of ur points...(24,91)...x = 24 and y = 91
sub and find b, the y int
91 = 9/8(24) + b
91 = 27 + b
91 - 27 = b
64 = b

so ur equation is : y = 9/8x + 64 <== slope intercept form

y = 9/8x + 64
-9/8x + y = 64
9x - 8y = -512
9x - 8y + 512 = 0 <== general form

point slope form...this can have 2 answers...
y - y1 = m(x - x1)using points (-40,19)
y - 19 = 9/8(x - (-40) =
y - 19 = 9/8(x + 40) <== this is one

y - y1 = m(x - x1)...using points (24,91)
y - 91 = 9/8(x - 24) <== this is the other one

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4