There are 15 cherry, 17 grape, and 14 orange juice boxes in the cooler. what is the probability of randomly selecting a cherry then selecting a grape without replacement?

question 3 options:

17/138

119/1058

136/1035

29/46

15 cherry, 17 grape, and 14 orangetotal of 46 juice boxes

P(cherry) = 15/46
without replacing
P(grape) = 17/45 (I put it over 45 because since the 1st was not replaced, we have 1 less juice box)

P (both events happening) = 15/46 * 17/45 = 17/138 <==

15 +17 +14 = 46 juice boxes total

15 cherry = 15/46

17 grape = 17/45

15/46 * 17/45 = 17/138

Arhombus is a quadrilateral.