An iceberg has a volume of 7660 cubic feet. what is the mass of the ice (in kg) composing the iceberg

Well to solve this problem, we need the density of ice. The density of ice is around 0.917 g / cm^3.

Now to find for the mass, simply multiply the volume with the density.

That is:

Mass = density * volume

However, let us convert first the volume into units of cm^3.

Volume = 7660 ft^3 = 2.1691 x 10^8 cm^3

Therefore the mass is:

mass = 0.917 g / cm^3 * 2.1691 x 10^8 cm^3

mass = 1.989 x 10^8 g

mass = 1.989 x 10^5 kg

your answer is a

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