How many bricks 3.75 in. wide × 8 in. long are required to cover a patio 13 ft. 6 in. wide by 18 ft 9 in. long ?
step 1. first, find the total width & length of the patio in inches.
step 1a. convert the portion of width and length that is expressed in feet to inches.
width: 13 ft = 13 × =
length: 18 ft = 18 × = in

1215 bricks will be required.

Step-by-step explanation:

Length of a brick L= 8 in. and width of the brick w = 3.75 in.

Area of one brick = 8×3.75 = 30 in²

Now length of a patio = 13 feet 6 in

since 1 feet = 12 inch.

So length of the patio = (13×12 + 6)= 162 in

Similarly width of the patio = 18 feet 9 inch = (18×12 + 9) = 216 + 9 = 225 inch

Area of the patio = 162×225 = 36450 in²

Now total bricks required to cover patio = Area of patio ÷ area of one brick

                                                                   = 36450 ÷ 30 = 1215 bricks

Therefore 1215 bricks will be required to cover a patio.

since both sides equal, there are infinitely many olutions.

452,489 to the nearest thousand is 452,000