An ant started at a distance of 20 cm from a camera and began crawling directly away from it. 5 seconds later, the ant was 28 cm from the camera. if d is the distance of the ant from the camera, what is (delta)d?

The ant started out 4 feet from its home. B.) The ant is crawling at 4 feet per minute. ... D.) The ant is 4 feet from its home after t minutes. ... Since distance is equal to velocity x time and t = time in minutes, the number 4 must .

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.