Acircle is centered at 7,8 and has a radius of 11 what is the equation?

(x − 7)2 + (y − 8)2 = 121

Step-by-step explanation:

I took the quiz and this was the correct answer. Although (x − 7)2 + (y − 8)2 = 11 was an answer choice it was incorrect. Here is proof from my quiz for verification.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )