If employee a logged 120 hours of travel in four years and employee b logged hours of travel at a 20% higher rate, how many more hours did employee b have than employee a after 1.5 years?

If employee A did 120 hours in four years, then he did 30 hours each year (120 divided by four is 30). 20% of 30 is 6 (because 30x0.20 is 6). In other words, employee B does 36 hours each year. To find how many hours employee B logged in 1.5 years, you'd multiply 1.5 by 36 (the number of hours B did), which would be 54 hours. Employee A did 45 hours ( 1.5x30=45). 54-45=9. In conclusion, Employee B did 9 more hours than Employee A after 1.5 years.

4+2=-2. 1+2=3. y=-2/3x+b. 2=4/3+b. 2/3=b. the answer is y= -2/3x+2/3

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