Segment pq bisects segment st at point r.

sr=2x+2 and st=40

find the length of segment sr.

a
sr=9
b
sr=40
c
sr=36
d
sr=20

2(2x+2)=40, 4x+4=40, 4x=36, x=9..plug in 9..

2x+2, 2×9+2, 18+2, 20=sr

Step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

f(x)=4

step-by-step explanation: