Asafety regulation states that the height h of a guardrail should be 106 centimeters with an absolute deviation of no more than 7 centimeters. write and solve an absolute value inequality that represents the acceptable heights of a guardrail. the absolute value inequality is_ . the acceptable range of heights of a guardrail are _cm to _cm.

The height h of a guardrail = 106 centimeters

absolute deviation =  7 centimeters

To find the acceptable heights of a guardrail , we add and subtract absolute deviation(7) from the mean height(106)

The acceptable range of height is 7 cm away from 106 to the left and then to the right.

106 + 7 = 113

106 - 7 = 99

acceptable heights are defined by

99 <=h<=113

The absolute value inequality is |x-106|<=7

The acceptable range of heights of a guardrail are 99 cm to 113 cm.

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.