The second side of a triangular deck is 3 feet longer than the shortest side and a third side that is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 68 feet, what are the lengths of the three sides?

The perimeter of a triangle is:

P = a + b + c

We are given that:

b = a + 3

c = 2 a – 3

Therefore:

68 = a + a + 3 + 2 a – 3

68 = 4 a

a = 17

and,

b = a + 3 = 20

c = 2a – 3 = 31

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

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step-by-step explanation:

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