The larger of two numbers is 10 less than twice the smaller number. if the sum of the two numbers is 38 ,find the two answers.

Assume that the larger number is m and the smaller one is n.
the larger is 10 less than twice the smaller, this means that:
m = 2n-10
the sum of the two is 38, this means that:
m+n = 38
substitute by the first equation in the second one:
2n-10+n=38
3n=48
n= 16
substitute by n in the first equation:
m=2n-10=2(16)-10= 22

based on this,
the larger number is 22 while the smaller number is 16

Ihave, but this question is gonna probably get deleted.