De bisects ab at c. if ac =8x-23 and cb=3x+22 find x

x = 9.

Step-by-step explanation:

Given  : DE bisects AB at C. If AC =8x-23 and CB=3x+22.

To find :  Find X.

Solution : We have given  DE bisects AB at C.

Bisector : A point which cut the line in to two equal parts.

ACB

AC = CB . ( C  bisect AB)

Plug the values.

8x - 23 = 3x + 23 .

On subtracting both sides by 3x

8x - 23 - 3x  = 22 .

5x - 23 = 22 .

On adding both sides by 23 .

5x = 23 +22 .

5x = 45 .

On dividing both sides by 5 .

x = 9.

Therefore, x = 9.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

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