The height of a soccer ball thrown of a hill can be modeled by the equation h = -16t^2 -8t +120. Where h is the height in feet and t is the time in
seconds. What was the initial height of the
soccer ball?

120 feet

Step-by-step explanation:

You have to find the y-intercept to calculate the initial hight, this can be done by substituting o in for t

h(0)= -16(0)^2-8(0)+120

=120ft

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10