Answers: 2
Mathematics, 21.06.2019 15:00
The radical equation 2+√2x-3 = √x+7 has a solution set [x= a0} and an extraneous root x = a1.
Answers: 3
Mathematics, 21.06.2019 18:30
What is the answer to this question? i'm a bit stumped. also how do i do it? 5(x - 4) = 2(x + 5)
Answers: 1
Mathematics, 21.06.2019 19:20
Which of the following quartic functions has x = –1 and x = –2 as its only two real zeroes?
Answers: 1
Mathematics, 21.06.2019 20:00
Evaluate the discriminant of each equation. tell how many solutions each equation has and whether the solutions are real or imaginary. 4x^2 + 20x + 25 = 0
Answers: 2
Help please! math assignment
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