The length of a rectangle is 2ft shorter than 5 times its width x the area of the rectangle is less than 100ft2. Which inequality can be used to determine the maximum width(ft) of the rectangle?

answer: r there any options?

step-by-step explanation:

explanation:

step-by-step explanation:

the answer is c

step-by-step explanation: i took a test with this question on it

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²