If light travels at a speed of 300,000,000 meters per second. Find the distance travelled by light in:
1 second

d) -1

step-by-step explanation:

table a is wierd

step-by-step explanation:

6*f

step-by-step explanation:

for the free

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629