find the value of r so that the line through (2,-3) and (-4,r) has a slope of -1/2 | please explain steps

r = 0

Step-by-step explanation:

slope formula is the difference of the y-values over the difference of the x-values

[r-(-3) / -4-2] = -1/2

r+3/-6 = -1/2

cross-multiply:

2(r+3) = (-1)(-6)

2r + 6 = 6

2r = 0

r = 0

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?