Twenty-four students took a test. Fourteen students earned an A and 10 students earned a B. A student will be randomly chosen. What is the probability that the student earned an A on the last test? Enter your answer as a fraction, in simplest form, in the box

idk

step-by-step explanation:

your victory is right around the corner. never give up.

- niki minaj

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

answer: i think its red because you have to see what it equals to

hope that

10 x 12 = 120 the tens to conte like 10,20,30,40 so i did that 12 times