√4x-3 +√2x+3=6

pls answer its​

X = 3

Step-by-step explanation:

STEP 1: Isolate a square root on the left hand side

Original equation

     √4x-3+√2x+3 = 6

     Isolate

     √4x-3 = -√2x+3+6

STEP 2: Eliminate the radical on the left hand side

Raise both sides to the second power

     (√4x-3)2 = (-√2x+3+6)2

After squaring    

4x-3 = 2x+3+36-12√2x+3

STEP 3: Get remaining radical by itself

 Current equation     

4x-3 = 2x+3+36-12√2x+3

 Isolate radical on the left hand side

12√2x+3 = -4x+3+2x+3+36

Tidy up 

12√2x+3 = -2x+42

STEP 4: Eliminate the radical on the left hand side

     Raise both sides to the second power

     (12√2x+3)2 = (-2x+42)2

     After squaring

     288x+432 = 4x2-168x+1764

STEP 5: Solve the quadratic equation

     Rearranged equation

      4x2  - 456x  + 1332 = 0

     This equation has two rational roots:

       {x1, x2}={111, 3}

STEP 6: Check that the first solution is correct

     Original equation, root isolated, after tidy up

     √4x-3 = -√2x+3+6

     Plug in 111 for  x 

      √4•(111)-3 = -√2•(111)+3+6

      Simplify

      √441 = -9

      Solution does not check

      21 ≠ -9 

STEP 7: Check that the second solution is correct

     Original equation, root isolated, after tidy up

     √4x-3 = -√2x+3+6

     Plug in 3 for  x 

      √4•(3)-3 = -√2•(3)+3+6

      Simplify

      √9 = 3

      Solution checks !!

     Solution is:

      x = 3

the answer is c)8

step-by-step explanaction: