ILL MARK BRAINLIEST PLEASE HELP!!! Pat is fencing two areas for their pigs and ducks. The length of one area is 2m more than double its width. The length of the other area is 3m less than its width. If the width of both areas is 6m, how much fencing will they need?

40 meters for area 1

12 meters for area 2 so combined it will be 52 meters

this one is hard

explanation is:

the length is 2m more than the width doubled and so the width is 6 so 6 times 2 is 12 + 2 (from the 2m longer) is 14 so then using the formula for rectangles (the shapes may be rectangles due to the lengths being different from the width) (length x 2) + (width x 2)= 40=28+12 and 6+12=18 now 18+ 40 combined gives us 52

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: