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Mathematics, 22.04.2021 23:30 karyme12
Change the quadratic equation y= x^2+4x-5 from standard form to vertex form.
1. Transpose the -value to the left side of the equation.
2. Complete the square of the expression on the right side of the equation to get a perfect square trinomial. Add the resulting term to both sides.
3. Add the numbers on the left and factor the trinomial on the right.
4. Transpose the number across to the right side to get the equation into the vertex form, .
5. Make sure the addition and subtraction signs are correct to give the proper vertex form.
a. y= (x---2)^2
b. Y+9=(x+2)^2
c. y= (x---2)^2---9
d. y= a (x-h)^2 + k
Y= [x - (-2)]^2+ (-9)
e. Y=(x+2)^2-9
f. Y+5 = x^2+4x
g. Y+5+_4_=x^2+4x+_4_
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Change the quadratic equation y= x^2+4x-5 from standard form to vertex form.
1. Transpose the -val...
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