Solve the system of equations
3x + 4y + 3z = 9
3x + 3y + 3z = 3
2x + 4y + 3z = 8

Given equations :

=》3x + 4y + 3z = 9 ( 1 )

=》3x + 3y + 3z = 3 ( 2 )

=》2x + 4y + 3z = 8 ( 3 )

taking equation ( 1 ) and ( 2 ) : -

=》3x + 4y + 3z = 9 ( 1 )

=》3x + 3y + 3z = 3 ( 2 )

subtract equation ( 2 ) from ( 1 )

=》3x + 4y + 3z - 3x - 3y - 3z = 9 - 3

=》y = 6

now, taking equation ( 1 ) and ( 3 )

=》3x + 4y + 3z = 9 ( 1 )

=》2x + 4y + 3z = 8 ( 2 ) from

subtracting equation (3) from (1)

=》3x + 4y + 3z - 2x - 4y - 3z = 9 - 8

=》x = 1

now, plugging the value of x and y in equation ( 1 )

=》3x + 4y + 3z = 9

=》(3 × 1) + (4 × 6) + 3z = 9

=》3 + 24 + 3z = 9

=》27 + 3z = 9

=》3z = - 18

=》z = -6

irrational, cannot

show da graph

step-by-step explanation: