Consider this absolute value function. f(3) = (+31
If function fis written as a piecewise function, which plece will it include?
A. -x- 3, x<3
B. -x + 3, x <-3
C. x+3, x >3
D. x+3, x>-3

D

Step-by-step explanation:

f(x) = |x+3|=x+3   when x+3≥0 ⇒x≥-3

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

21

jk it's 20

step-by-step explanation: