In ΔJKL, the measure of ∠L=90°, the measure of ∠J=9°, and KL = 49 feet. Find the length of JK to the nearest tenth of a foot.

could you reply to this with the question so i can ?

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just for that im not answering

6/20

step-by-step explanation:

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

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told you