Luiza's savings account had $50 in its first year. Each year since then, her account accumulated interest
amounting to 15% of the balance in the previous year.
Let g(n) be Luiza's account balance at the nth
year of the saving.
g is a sequence. What kind of sequence is it?

50(1.15)^n-1

Step-by-step explanation:

1. Let's consider the first three terms of g(n) to get a sense of how the function values change as n increases.

2. The first term is Luiza's account balance at the first year of the saving, which is the initial amount she deposited. We know this to be $50.

The second term is Luiza's account balance at the second year. Since the account accumulated 15% each year, it was 1.15 times the balance in the first year, which is $50*1.15=$57.50.

The third term is Luiza's account balance at the third year. Again, this is 1.15 times the balance of the year before that, which is $57.50*1.15=$66.125.

To summarize:

g(1)=50   g(2)=50*1.15   g(3)=50*1.15*1.15

We can see that each term is 1.15 times its preceding term. There is a constant ratio between consecutive terms. Therefore, this is a geometric sequence.

3. We can write an explicit formula for this geometric sequence using the form A*B^n-1. In this form,  A,  is the first term and B is the common ratio. What are the appropriate values for our case?

The first term is Luiza's initial deposit, which is $50.

The common ratio corresponds to the percentage of accumulated interest. Since that percentage is 15%, the common ratio is 1.15.

4. In conclusion, g is a geometric sequence.

An explicit formula for the sequence is g(n)=50*1.15^n-1

Note that this solution strategy results in this formula; however, an equally correct solution can be written in other equivalent forms as well.

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

go hook jvc hgv cj xk jvc 6756