EFGH is a rhombus. Rhombus E F G H is shown. Diagonals are drawn from point E to point G and from point F to point H. All sides are congruent. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

there are no figures how am i supposed to answer this question

step-by-step explanation:

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation:

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: