A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 125x + 147

The maximum height of the rocket is about 391.1 feet.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is modeled by the equation:

We want to find the maximum height reached by the rocket.

Since this is a quadratic equation, the maximum height occurs at the vertex. The vertex of a quadratic is given by:

In this case, a = -16, b = 125, and c = 147.

Thus, the x-coordinate of our vertex is:

To find the maximum height, we will substitute this value back in. So:

The maximum height of the rocket is about 391.1 feet.

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)