If -1 is one of the zeroes of py 3x^3-5x^2-11x-3 find other zeroes

(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4)

and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2)

Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3)

There is not enough information on this sorry can you take a picture of it and put it on here