The graph of the function f(x) = ax^2 + bx + c has vertex at (0, 2) and passes through the point (1, 8). Find a, b and c
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Step-by-step explanation:

You need to use vertex form of a quadratic to solve this.

Consider the vertex to be

Now all you have to do is solve for a.  You know that the vertex is and you have know the point of .  Now, all you have to do is plug in these values and solve for a.

Now you know the equation is , but you need it in quadratic form.  All you have to do is solve is distribute the 6:

You get:

a = 6

b = 0

c = 2

no

step-by-step explanation:

answer