For positive acute angles A
A and
B
,
B, it is known that
cos
⁡
A
=
24
25
cosA=
25
24
​
and
tan
⁡
B
=
11
60
.
tanB=
60
11
​
. Find the value of
cos
⁡
(
A
−
B
)
cos(A−B) in simplest form.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

b, i believe, but not sure.

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation:

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step-by-step explanation: