Start with x ^ 2 - 6x + 8 = 0 and complete the squarewhat is the equivalent equation A) (x + 3) ^ 2 = 1 B) (x + 3) ^ 2 = 9 (x - 3) ^ 2 = 1 D) (x - 3) ^ 2 = 9

there is nothing below so i cannot

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.