HELP! LINKS WILL BE REPORTED!!! Below is the graph of equation y=−|x+2|-1. Use this graph to find all values of x such that

1. y > 0

2. y < 0

3. y = 0

Please add a real answer! No links!

Thx so much for helping!

steps below

Step-by-step explanation:

vertex of y=−|x+2|-1 is (-2 , -1), y ≤ -1

1. y>0     No x value will get y>0

2. y<0    x: real number -∞ -> ∞ get y value ≤ -1

3. y=0    No x value get y = 0

Domain:  -∞ -> ∞

Range: y ≤ -1

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.