What is the circumference of a circle to the nearest hundredth of a foot, if the radius of the circle is 7 feet?

43.98

Step-by-step explanation:

43.98

Step-by-step explanation:

First you must plug 7 into the formula, (C=2π r)

C= 2 π 7

C = 2(21.9911485751)

C= 43.9822971503

Round it to the nearest hundredth and you get 43.98 Feet

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²