Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms. 2g – 4g3 + 5g2 – 1

A–4g3 + 5g2 + 2g – 1; cubic polynomial

B–1 + 2g + 5g2 – 4g3 ; cubic binomial

C4g3 – 5g2 + 2g – 1; cubic trinomial

D5g3 – 4g2 + 2g – 1; quadratic binomial

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

what is the information provided?

step-by-step explanation: